Help with single slit diffraction (fraunhoffer)

  • Thread starter j-lee00
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urgent Help with single slit diffraction (fraunhoffer)

why is it a minimum at a*sin ([tex]\theta[/tex]) = m*[tex]\lambda[/tex],

a = slit separation


I would have thought if the path difference is equal to a whole wavelength then there would be constructive interference??

See http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html
 
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Answers and Replies

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Doc Al
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Don't confuse the double slit interference condition (http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/slits.html#c1").

In the single slit condition, when the light from opposite ends of the slit have a full wavelength phase difference, that means that half the light from the slit is exactly one half wavelength out of phase with the other half. Which mean destructive interference.
 
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