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Help with single slit diffraction (fraunhoffer)

  1. Dec 2, 2007 #1
    urgent Help with single slit diffraction (fraunhoffer)

    why is it a minimum at a*sin ([tex]\theta[/tex]) = m*[tex]\lambda[/tex],

    a = slit separation

    I would have thought if the path difference is equal to a whole wavelength then there would be constructive interference??

    See http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html
    Last edited: Dec 2, 2007
  2. jcsd
  3. Dec 2, 2007 #2

    Doc Al

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    Staff: Mentor

    Don't confuse the double slit interference condition (Double Slit Interference) with that for a single slit (Single Slit diffraction).

    In the single slit condition, when the light from opposite ends of the slit have a full wavelength phase difference, that means that half the light from the slit is exactly one half wavelength out of phase with the other half. Which mean destructive interference.
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