1. The problem statement, all variables and given/known data Find the volume obtained by rotating the region between the graph of y=0.5(sin(x^2)^2) and the x-axis (from 0 to squareroot pi) about the y-axis. The answer pi^2/4, but I don't understand how to get the answer, I can set up the integral but can't simplify it to that answer. 2. Relevant equations y=0.5(sin(x^2)^2) 3. The attempt at a solution First to get the radius in terms of y -> y=0.5sin^2(x^2), thus √arcsin(√2y)=x The volume is thus calculated via the disk method and is equal to the integral of pi√arcsin(√2y), from 0 to √pi. I don't know where to go form there,maybe I didn't set up the integral correctly?