Hermite polynomial and transformation

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SUMMARY

The discussion centers on the Fourier transformation of Hermite polynomials in the context of quantum harmonic oscillators. The transformation is defined as \(\mathcal{F} \left\{ \exp (-x^2/2) H_n(x) \right\} = (-i)^n \exp (-k^2/2) H_n(k)\). The user seeks to express this result in terms of momentum \(p\), using the relationship \(p = \hbar k\). The discussion clarifies that, despite general convolution rules for Fourier transforms, the specific case of Hermite polynomials allows for a simple product in \(k\) space.

PREREQUISITES
  • Understanding of Fourier transformations
  • Familiarity with Hermite polynomials
  • Knowledge of quantum harmonic oscillators
  • Basic concepts of momentum and wavenumber relations
NEXT STEPS
  • Research the properties of Hermite polynomials in quantum mechanics
  • Study Fourier transformation techniques in quantum physics
  • Explore the relationship between wavenumber \(k\) and momentum \(p\) in detail
  • Investigate convolution theorems in Fourier analysis
USEFUL FOR

Physicists, mathematicians, and students studying quantum mechanics, particularly those focusing on quantum harmonic oscillators and Fourier analysis of special functions.

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In the chapter of quantum harmonic oscillator, we use the Hermite polynomial a lot. And the Fourier transformation of Hermite polynomial (in wavenumber space) gives

[tex]\mathcal{F} \left\{ \exp (-x^2/2) H_n(x) \right\} = (-i)^n \exp (-k^2/2) H_n(k)[/tex]

Now I need to find the similar result in terms of momentum p, I know the relation between wavenumber and momentum is

[tex]p = \hbar k[/tex]

But I still cannot transform above result to that written in terms of p. Any clue?
 
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If you FT a product of two functions of x, you should get a convolution in k space, not a simple product.
 
clem said:
If you FT a product of two functions of x, you should get a convolution in k space, not a simple product.

But I am talking about a special case: Hermite polynomial, so in this case, the above equation is correct. They are just simple product in k space
 

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