High school math (population & exponents)

AI Thread Summary
The discussion focuses on calculating the doubling time of the world’s population, which grew at a rate of 1.85% per annum from 1950 to 1989. The doubling time is determined to be approximately 39 years using the formula dt = 72%/growth rate. Additionally, the population in 1989 is calculated by applying the growth rate to the initial population of 2.5 billion over 39 years, resulting in an approximate population of 6.6 billion. A more rigorous approach involves using the equation N = N0 * 1.085^n and solving for n using logarithms. This method confirms the calculations and provides a deeper understanding of exponential growth.
novawinters
Messages
5
Reaction score
0

Homework Statement


7. Between 1950 and 1989, the world’s population grew by 1.85%/a.
(a) Determine the doubling time for this example.
(b) If the population in 1950 was 2.5 billion, what was it in 1989?


Homework Equations


dt = 72%/growth rate


The Attempt at a Solution


a. dt = 72%/1.85%/a = 39 a
b. 1989-1950 = 39 years
2.5 billion multiplied 1.85%^39
6.6 x 10^19
 
Physics news on Phys.org
That's approximately correct. To do the problem rigorously, we can write:

N=N0*1.085^n
N/N0=1.085^n
2=1.085^n

and then solve for n by taking the log of both sides.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top