Higher-Order Differential Equations

recon_ind
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Homework Statement



Find the general solution of the given higher-order differential equation.

d3x/(dt3) - d2x/(dt2) - 4x = 0

Homework Equations



Use an auxiliary equation such as m3 - m2 - 4 = 0

The Attempt at a Solution



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That is the auxiliary equation you want to use. As it turns out, the left side can be factored, yielding (m - 2)(m2 + m + 2) = 0

There are three distinct solutions, so the solution to this homogeneous problem will be x(t) = c1e2t + c2em2t + c3em3t. All you have to do is find the other two constants, m2 and m3.
 
So, I should just use the quadratic formula to find the other two solutions?

Thanks man.
 
The other two solutions are of the form \alpha \pm \beta
 
recon_ind said:
So, I should just use the quadratic formula to find the other two solutions?
Yes. And yes, the two solutions are of the form a +/- b. One of your values of m will be a + b, and the other will be a - b.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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