# Hight Function!

bayan
Hi guys.

I was doing a SAC and there were two questions

one was $$y=\frac {1}{X^2}-1$$ and the other was $$y=\frac {-1}{X^2}+4$$

I got the hight function to be $$h=e^\frac{V}{\pi}-1$$ where V is the volume and max hight is 3 for the first function $$y=\frac {1}{X^2}-1$$

Can someone help me to find the hight function of the other function plz.

The Volume of both graphs are same.

bayan
is this the hight function of second function??? $$h=e^\frac{-V}{\pi}-4$$

Homework Helper
would you mind defining a 'hight' function. I can find no references for it (other than misspelling it as height when it is defined for abelian groups according to planet math)

Homework Helper
bayan said:
Hi guys.

I was doing a SAC and there were two questions

one was $$y=\frac {1}{X^2}-1$$ and the other was $$y=\frac {-1}{X^2}+4$$

$$y= \frac{1}{X^2}-1$$ is not a question- it is a function or equation. What was the question??

I got the hight function to be $$h=e^\frac{V}{\pi}-1$$ where V is the volume and max hight is 3 for the first function $$y=\frac {1}{X^2}-1$$

Can someone help me to find the hight function of the other function plz.

The Volume of both graphs are same.

I didn't know a graph had a volume! I assume "hight" was a misprint for "height" but I'm still not sure what you mean by the "height" of a function.

Last edited by a moderator:
bayan
HallsofIvy said:
$$y= \frac{1}{X^2-2}-1$$ is not a question- it is a function or equation. What was the question??

I didn't know a graph had a volume! I assume "hight" was a misprint for "height" but I'm still not sure what you mean by the "height" of a function.
Sorry about my BAD english but all I intended to say is how can I find the rate of change of height with respect to change in volume from the second equation.

Hope that makes it abit more clear.