- #1

bayan

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I was doing a SAC and there were two questions

one was [tex]y=\frac {1}{X^2}-1[/tex] and the other was [tex]y=\frac {-1}{X^2}+4[/tex]

I got the hight function to be [tex]h=e^\frac{V}{\pi}-1[/tex] where V is the volume and max hight is 3 for the first function [tex]y=\frac {1}{X^2}-1[/tex]

Can someone help me to find the hight function of the other function plz.

The Volume of both graphs are same.

Thanx in advance.