Hilbert action according to robert wald

  • Thread starter Thread starter naughtyeskimo
  • Start date Start date
  • Tags Tags
    Hilbert
naughtyeskimo
Messages
3
Reaction score
0
hi everyone
i'm brand new to forums and I'm holdin a seminar on a variation of the hilbert action as described in wald's book general relativity. if anyone knows that book and topic pretty well maybe you can help me, my question is this:

for the variation \delta R_{ab} with respect to parameter \lambda of the ricci tensor R_{ab} wald uses a result from the end of chapter 7, where he assumes g_0^{ab} to be a solution of einstein's equation, so in the calculation of \delta R_{ab} he assumes already that R_{ab} = 0 at $\lambda = 0$ so he works it out in terms of the tensor C^c_{ab} (the tensor difference between two covariant derivatives).

my problem is: he uses einstein's equation on the unperturbed metric to fish out \delta R_{ab}, then uses that to derive einstein's equation with the hilbert action.

is there a good explanation for using this equation to derive this very same equation? i hope i explained myself clearly enough.

thanks in advance
 
Last edited:
Physics news on Phys.org
Carroll's derivation seems pretty straight forward (see pg. 114): http://preposterousuniverse.com/grnotes/grnotes-four.pdf
 
Last edited by a moderator:
thanks very much, that is an easier method. good work.
 
That's one reason I've never really liked Wald's book. Some things are being made much more complicated than necessary, unless you're a die-hard mathematician. Indeed, the easiest way is to apply the variation directly to the definition of the Ricci tensor and use covariance arguments (or do the whole calculation).
 
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. The Relativator was sold by (as printed) Atomic Laboratories, Inc. 3086 Claremont Ave, Berkeley 5, California , which seems to be a division of Cenco Instruments (Central Scientific Company)... Source: https://www.physicsforums.com/insights/relativator-circular-slide-rule-simulated-with-desmos/ by @robphy
Abstract The gravitational-wave signal GW250114 was observed by the two LIGO detectors with a network matched-filter signal-to-noise ratio of 80. The signal was emitted by the coalescence of two black holes with near-equal masses ## m_1=33.6_{-0.8}^{+1.2} M_{⊙} ## and ## m_2=32.2_{-1. 3}^{+0.8} M_{⊙}##, and small spins ##\chi_{1,2}\leq 0.26 ## (90% credibility) and negligible eccentricity ##e⁢\leq 0.03.## Postmerger data excluding the peak region are consistent with the dominant quadrupolar...
Back
Top