Hilbert Space: f(x) = x^n on Interval (0,1)

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SUMMARY

The function f(x) = x^n is in Hilbert space on the interval (0,1) if the integral ∫01 |f(x)|2 dx converges. This integral evaluates to ∫01 x2n dx, which converges for n > -1. Therefore, the range of n for which f(x) is square integrable in Hilbert space on the specified interval is n > -1.

PREREQUISITES
  • Understanding of Hilbert space concepts
  • Knowledge of square integrable functions
  • Familiarity with definite integrals
  • Basic calculus skills
NEXT STEPS
  • Study the properties of Hilbert spaces and their applications
  • Learn about square integrable functions in more detail
  • Explore convergence criteria for integrals
  • Investigate the implications of different values of n on function behavior
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Mathematicians, physics students, and anyone studying functional analysis or working with Hilbert spaces.

Gumbercules
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Homework Statement


for what range of n is the function f(x) = x^n in Hilbert space, on the interval (0,1)? assume n is real.


Homework Equations



functions in Hilbert space are square integrable from -inf to inf

The Attempt at a Solution


I am having trouble with the language of the problem and the concept of the Hilbert space in general. Does 'on the interval (0,1)' mean that the square integrable function only has to converge for limits of integration between 0 and 1?
 
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Yes they are asking you for what n the following integral converges.

<br /> \int_0^1 |f(x)|^2 dx &lt;\infty<br />
 
Thanks!
 

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