Horizontal Tangent Lines: Intersection of Cylinder and Plane

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SUMMARY

The discussion focuses on finding horizontal tangent lines at the intersection of the plane defined by z = x + 2y and the cylinder described by x² + y² = 1. The vector function representing their intersection is r(t) = cos(t)i + sin(t)j + (cos(t) + 2sin(t))k, with its derivative r'(t) = -sin(t)i + cos(t)j + (-sin(t) + 2cos(t))k. The key conclusion is that the tangent vector is horizontal when its k component is zero, not when r'(t) equals zero. Participants clarify that the horizontal tangent condition requires the j component to be zero, leading to the equation 2cos(t) - sin(t) = 0.

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Lothar
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Homework Statement



Consider the plane z = x + 2y and the cylinder x^2 + y^2 = 1

(a) Find a vector function r(t) describing their intersection.
(b) Find the points if any where the tangent to ~r is horizontal
(c) Find an equation for the tangent line to ~r at each of these points.

Homework Equations

The Attempt at a Solution



r(t) = cos(t)i+sin(t)j+(cos(t)+2sin(t))k
r'(t) = -sin(t)i + cos(t)j + (-sin(t)+2cos(t))k

These equations are correct, as I have plotted them in Maple 14 and the images appear correct. I'm having issues finding the horizontal tangent, and then finding the equations afterwards.
The horizontal tangent should be when r'(t) = 0 correct? I cannot find a value that makes this true. Maybe I'm making a mistake in my thinking?

Thank you for any help.
 
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Hi Lothar! :smile:

(try using the X2 icon just above the Reply box :wink:)
Lothar said:
The horizontal tangent should be when r'(t) = 0 correct?

No.

r' is a vector, it will be horizontal when … ? :wink:

(if r' was zero somewhere, you'd have a dodgy parameter! :rolleyes:)
 
tiny-tim said:
Hi Lothar! :smile:

(try using the X2 icon just above the Reply box :wink:)


No.

r' is a vector, it will be horizontal when … ? :wink:

(if r' was zero somewhere, you'd have a dodgy parameter! :rolleyes:)


Where r' is equal to pi or 2pi? Maybe? I'm kind of lost now.
 
Are we talking about the same thing? :confused:

r' is a vector, of the form (a,b,c) or ai + bj + ck

it can't be a number like π ror 2π …

when will that vector be horizontal?​
 
tiny-tim said:
Are we talking about the same thing? :confused:

r' is a vector, of the form (a,b,c) or ai + bj + ck

it can't be a number like π ror 2π …

when will that vector be horizontal?​

I'm not sure. That's why I asked.
When the j component is equal to zero?
 
Lothar said:
When the j component is equal to zero?

Nearly :rolleyes: … the k component! :wink:

(isn't that obvious … "horizontal" means moving only in the x,y plane, so no z ?)
 
Well I'm stupid. Still though, I don't see a point on the unit circle where 2cost - sint is equal to zero.
 
tant = 2 :smile:
 

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