Horizontal veolocity given vertical velocity and angle

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SUMMARY

The discussion revolves around calculating the horizontal velocity of a train given the vertical velocity of raindrops falling at 8.7 m/s and an angle of θ = 67° observed from the train. The correct approach involves using trigonometric functions rather than the Pythagorean Theorem. Specifically, the horizontal component of the velocity can be determined using the tangent function, where the horizontal velocity (Vx) equals the vertical velocity divided by the tangent of the angle.

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IAmSparticus
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Homework Statement


A person looking out the window of a stationary train notices that raindrops are falling vertically down at a speed of 8.7 m/s relative to the ground. When the train moves at a constant velocity, the raindrops make an angle of θ = 67° when they move past the window as the drawing shows. How fast is the train moving?



Homework Equations


Vx = V0x +axt


The Attempt at a Solution


3.4 and 22.3 m/s are both incorrect.

Couldn't figure out how to do it since clearly you don't just use the Pythagorean Theorem... walk me through it?
 
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Hi IAmSparticus! :wink:

You'd only use Pythagoras if you wanted the length of the third side.

But you only want the angle … so use cos or sin or tan. :smile:
 

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