Calculating Horizontal Component of Raindrop Velocity on Moving Train

[Toranc3]

Homework Statement

When a train's velocity is 12.0 m/s eastward, raindrops that are falling vertically with respect to the Earth make traces that are inclined 30.0 degrees to the verical on the windoes of the train.

A. What is the horizontal componenet of a drop's velocity with respect to the earth?

B. What is the horizontal component of a drops velocity with respect to the train?

Homework Equations

V(r/t) =V(r/g)+V(g/t)

(r/t)= veolocity of rain with respect to the ground(earth)
(g/t) velocity of the train with respect to the ground but negative.

The Attempt at a Solution

For part a well since it says the rain drops vertically with respect to the Earth that must mean that it only has a vertical component.

For part b I am not sure how I would go about that to calculate it.

 

[Toranc3]

Do I break the vector of the rain into components?

 

[azizlwl]

Just imagine looking at a window of the train.
You see a raindrop just at the centre of top of the window and travels down.
Where will the raindrop at the bottom of the window? Left, middle or right if the train is going to the right.

 

[Toranc3]

Just imagine looking at a window of the train.
You see a raindrop just at the centre of top of the window and travels down.
Where will the raindrop at the bottom of the window? Left, middle or right if the train is going to the right.

to the left?

 

[azizlwl]

It is to the left due to train velocity and down due to rain vertical velocity(down).
If 1 sec. the train goes the right(12m) then you can find the vertical velocity using trig. function where opposite equal to 12 and the angle between adjacent and hypotenuse is 30°.