Horz./vert. components of force

  • Thread starter Thread starter bigtymer8700
  • Start date Start date
  • Tags Tags
    Components Force
AI Thread Summary
The discussion focuses on resolving the forces acting on a trunk being dragged up a ramp with a 20-degree slope. The man applies a pulling force of 381N at a 30-degree angle to the ramp, prompting questions about calculating the horizontal and vertical components of this force. Participants suggest rotating the coordinate axis to align with the ramp for easier calculations and emphasize the importance of understanding gravitational forces in this context. One user reports achieving the correct component values of 245N for the x-component and 292N for the y-component, seeking clarification on the solution process. The conversation highlights the need for clear problem-solving steps in physics homework.
bigtymer8700
Messages
40
Reaction score
0

Homework Statement


A man is dragging a trunk up the loading ramp of a mover's truck. The ramp has a slope angle of 20.0, and the man pulls upward with a force of magnitude 381N whose direction makes an angle of 30.0 with the ramp.

Im in need of some help I can't seem to figure out how to get each component of the force I know each has its own force in the x and y

http://session.masteringphysics.com/problemAsset/1027434/4/1027434.jpg
 
Last edited:
Physics news on Phys.org
I would start off by rotating my axis so they match with the ramp axis, which I'm sure you have done in class, then figure out the gravitational force down the ramp and the pulling force up the ramp. If you want more help you will have to be more specific and show what part you are stuck on.
 
hmm actually no i never rotated the axis i couldn't figure out how to solve the problem. i ended up with the answers I am just trying to get an idea of how it was solved. I got 245N for the x components and 292N for the y
 
Last edited:
You must have done a lot of algebra then, but you ended up with the right answer (good if so)? Can I see what you did?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
20
Views
5K
Replies
5
Views
9K
Replies
7
Views
5K
Replies
2
Views
2K
Replies
1
Views
9K
Replies
2
Views
10K
Replies
1
Views
6K
Back
Top