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maajdl said:You got the right answer, since f(zo)=1.
You use the Cauchy integral when you have to evaluate an integral that matches the pattern of a Cauchy integral!
Sometimes, the contour needs to be closed to get a match and the integral on the closing path can be evaluated by some other means.
The Cauchy integral is very useful in physics and in signal theory.
MissP.25_5 said:Hello.
How do I know when to use Cauchy integral formula. Why do we use the formula in this question? As you can see in my attempt, I got stuck.
Are my values for f(z), z, z0 here correct?
Ray Vickson said:I never look at photo attachments of handwritten work; in fact, if you read the "PF Guidelines" post by vela, you will see that you are not supposed to use them except for very special circumstances---for several good reasons. You should take the trouble to type out your work if you want the helpers to take the trouble to offer free assistance.
Cauchy's integral formula is a mathematical theorem that relates the values of an analytic function inside a closed contour to the values of the function on the contour itself. It is named after the French mathematician Augustin-Louis Cauchy.
Cauchy's integral formula is used when solving complex integrals over closed paths in the complex plane. It is also used to evaluate derivatives of complex functions and to solve boundary value problems.
To use Cauchy's integral formula, you first need to identify the function and the contour over which you want to integrate. Then, you need to ensure that the function is analytic (i.e. it is differentiable at every point inside the contour). Finally, you can apply the formula to calculate the value of the integral.
The key components of Cauchy's integral formula are the function, the contour, and the Cauchy integral formula itself, which includes a complex integral and the function's values on the contour.
No, Cauchy's integral formula can only be used for analytic functions, meaning they are differentiable at every point inside the contour. Non-analytic functions, such as those with singularities or discontinuities, cannot be evaluated using this formula.