How Are Proton Energies Quantized in a Nano-Scale Box?

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    De broglie Wave
AI Thread Summary
The discussion focuses on quantizing the energy of a proton confined in a nano-scale box with rigid walls. It establishes that the allowed de Broglie wavelengths are given by λ = 2L/n, where n is a positive integer, due to the standing wave condition. The kinetic energy of the proton can be derived using the relationship K = p²/2m, incorporating the de Broglie wavelength to express it as K = h²/2λ²m. The values for kinetic energy are computed for n = 1 and 2, confirming the quantization of energy levels. The calculations and derivations presented align with quantum mechanics principles.
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Homework Statement


A free proton moves back and forth between rigid walls separated by a distance L = 0.01 nm.
a) If the proton is represented by a one-dimensional standing de Broglie wave with a node at each wall, show that the allowed values of the de Broglie wavelength are given by λ = 2L/n, where n is a positive integer.
b) Derive a general expression for the allowed kinetic energy of the proton and compute the values for n = 1 and 2.

Homework Equations


K = p2/2m
λ = h/p

The Attempt at a Solution



The first part seems simple, I could graphically derive that L must equal nλ/L if there are nodes at each end. What I want to make sure about is part b. Would I have to use K = p2/2m, use the mass of a proton, and plug in p = h/λ getting K = h2/2λ2m?
 
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Kavorka said:
... L must equal nλ/L...
Just a little typo here.

Your work looks good.
 
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