How Can Euler's Identity Be Applied to Write Phasor Equations v(t) and I(t)?

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Discussion Overview

The discussion revolves around the application of Euler's identity to express phasor equations for voltage and current in time-domain functions, specifically v(t) and i(t). Participants explore the conversion process and subsequent calculations related to power.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents phasor representations for voltage and current, asking how to express them in time-domain functions.
  • Another participant suggests using Euler's identity and emphasizes taking the real part of the expression.
  • A participant derives time-domain functions for voltage and current, seeking further assistance on calculating power.
  • There is a discussion about the cosine identity provided for simplifying the product of two cosine functions.
  • Clarification is sought regarding the arguments A and B in the cosine identity, with a participant proposing specific values.
  • A later reply explains that A and B refer to the arguments of the cosine functions derived from the time-domain expressions.

Areas of Agreement / Disagreement

Participants generally agree on the use of Euler's identity and the approach to derive time-domain functions, but there is some uncertainty regarding the application of the cosine identity for power calculation.

Contextual Notes

The discussion includes assumptions about the definitions of voltage and current in phasor form and the application of trigonometric identities, which may not be fully resolved.

Who May Find This Useful

Students and practitioners interested in electrical engineering, particularly those studying phasor analysis and power calculations in AC circuits.

teng125
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for phasor, v = 20V e^(-j60) and i = 0.5A e^(-j30)
how can i write them in v(t) and I(t) ??
pls help


thanx
 
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Use Euler's identity and take only the real part.

[itex]e^{j \theta} = \cos \theta + j \sin \theta[/itex]

- Warren
 
i got v(t) = 20V cos (wt - 60 ) and i(t) = 0.5A cos(wt - 30)
from here,how to find p(t)??
a hint is given but i don't understand : coa A cos B = 1/2[cos(A+B) + cos(A-B)]
 
Power is voltage * current, yes?

Multiply your v(t) and i(t) to get p(t).

The cosine identity was given to you to help you with the simplification.

- Warren
 
so what is A and B?? is it -60 and -30??
 
A is the argument of the one cosine function; B is the argument of the other.

When you multiply two cosine functions, with arguments A and B, you can use the identity you provided to simplify.

In this case, A = wt - 60, and B = wt - 30.

- Warren
 

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