How can I calculate the cooling time of a steel ball using thermal radiation?

AI Thread Summary
To calculate the cooling time of a steel ball using thermal radiation, the discussion centers on the application of the Stefan-Boltzmann law and the integration of power equations. The user initially derived a formula for time but arrived at an incorrect result of 51 seconds instead of the expected 313 seconds. The error was identified in the integration step, where the user miscalculated the limits of the integral. Correcting this mistake leads to the accurate cooling time of approximately 313 seconds. The conversation emphasizes the importance of careful algebraic manipulation in solving physics problems.
mstrakl
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Homework Statement


Hi! I need some help by my phisycs homework at universty. Here is the problem:
We have a steel ball, with density of 7800kg/m^3, with speficic heat capacity 460J/kgK. Temperature of the ball is 1700K. How much time does the ball need to cool down to half of it's temperature (850K), if it cools only because of the thermal radiation. Stefan-Boltzman constant is 5,67×10^-8. There is no other radiation on the ball, from the surrounding area.
The ball's mass is 1kg.

Homework Equations




The Attempt at a Solution


I suppose, that the power of radiation (P = j × A = (s.b. constant) × T^4 × A) is decreasing as the temperature drops, so i tried to set up my equaton with differentials:

dQ = Pdt
mc dT = A × (sb const.) × T^4 dt

i integrated the equation, and got this:
mcT^-4dT = A(sb const)dt
-1/3 mcT^-3= A(sb const) × t

integral is from Ta/2 to Ta

and i shrinked the expression and expressed time from the equation

t= 8mc/(Ta)^3×A×(sb. const)

; c= spec. heat capacity
sb const. = stefan boltzman constante = 5,67 × 10^-8
Ta = temp. at start = 1700K

the result i get is 51 secons. The solution should be 313 seconds. What am I doing wrong? Can you help me?
 
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mstrakl said:
mcT^-4dT = A(sb const)dt
-1/3 mcT^-3= A(sb const) × t

integral is from Ta/2 to Ta

and i shrinked the expression and expressed time from the equation

t= 8mc/(Ta)^3×A×(sb. const)

Check your algebra... when solving the integral you should have a 7 instead than 8... anyway (using of course 7) I have the right result...
 
I did the algebra again, I hope photo sharp enough
... i get the same result, I checked twice.

51,14 seconds.

The correct result should be 313 seconds :S
 

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I probably found your problem... when computing
$$ \left(\frac{1}{T^3}\right)_{T/2}^{T}=\frac{1}{T^3/8}-\frac{1}{T^3}=\frac{8}{T^3}-\frac{1}{T^3}=\frac{1}{T^3}(8-1) $$
instead you computed
$$ \frac{1}{T^3/8 -T^3} $$
which is clearly different because then you don't get a factor 1/8...
Using the right formula you should have 313 more or less (I did it before and it was OK) :smile:
 
Oh of course... I have found the problem now... Thanks :)
 
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