How can i calculate the exact amount of heat absorbed by a black paint

AI Thread Summary
To determine the temperature rise of a black-painted steel plate, understanding the heat absorption characteristics is crucial, particularly the heat absorption coefficient. While a black surface can be approximated as a perfect absorber, variations in paint types can affect results due to differing emissivities and temperature-dependent characteristics. Theoretical calculations are complicated by multiple heat transfer methods, including conduction and convection, which introduce additional variables. If the paint is thin and the environment is uniform, it may be reasonable to assume thermal equilibrium between the paint and the steel. Overall, the discussion emphasizes the complexity of accurately predicting temperature changes in painted surfaces.
chetanladha
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Hi.
Knowing the LRV, heat source and all other relevant details, how can we deduce the exact temp rise with black colour (or any other colour for that matter)??
 
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chetanladha said:
Hi.
Knowing the LRV, heat source and all other relevant details, how can we deduce the exact temp rise with black colour (or any other colour for that matter)??

What are your thoughts on the problem?
 
i think just like we do for metals, if we know the heat absorption coefficient, then it can be done.
But unfortunately i can't find anything named "heat absorption coefficient" for black colour.
Is there any equivalent?
 
If the body is painted black then you can get approximate answers by treating it as a black body(perfect absorber/radiator).For other colours you can refer to the heat absorption coefficient(emissivity)but I doubt if you can get perfect data because different paints,even those that might look the same,have different characteristics.To add to the complications some paints have spectral emissivities that are are temperature dependant.
It seems that you are tackling a problem that can very complicated.Radiation is not the only method of heat transfer since you also have convection and conduction and possibly evaporation/condensation.There are so many variables.
If you gave more details about what exactly it is you are trying to do people here might be able to give you more advice.Am I right in guessing that you are starting a project with an emphasis on practical work which is about comparing the radiation/absorption characteristics of different surfaces?
 
Dadface said:
If the body is painted black then you can get approximate answers by treating it as a black body(perfect absorber/radiator).For other colours you can refer to the heat absorption coefficient(emissivity)but I doubt if you can get perfect data because different paints,even those that might look the same,have different characteristics.To add to the complications some paints have spectral emissivities that are are temperature dependant.
It seems that you are tackling a problem that can very complicated.Radiation is not the only method of heat transfer since you also have convection and conduction and possibly evaporation/condensation.There are so many variables.
If you gave more details about what exactly it is you are trying to do people here might be able to give you more advice.Am I right in guessing that you are starting a project with an emphasis on practical work which is about comparing the radiation/absorption characteristics of different surfaces?

Hi.
My work is very close to comparing the radiation/absorption characteristics of metal plate painted with different colours.
So, if there is a steel plate painted black, can i take the rise in temperature of paint to be the final temperature of the steel plate. (Assuming that the paint passes all of its heat to the parent metal.)

Tackling individual paint or steel plate if fine, but does the same hold true when you are talking about a steel plate painted black?
 
chetanladha said:
Hi.
My work is very close to comparing the radiation/absorption characteristics of metal plate painted with different colours.
So, if there is a steel plate painted black, can i take the rise in temperature of paint to be the final temperature of the steel plate. (Assuming that the paint passes all of its heat to the parent metal.)

Tackling individual paint or steel plate if fine, but does the same hold true when you are talking about a steel plate painted black?

I think this is such a difficult problem to deal with theoretically because there are so many variables just one other being connected with the thermal conductivity of the paint.I think that if the paint is thin enough,and if all the surroundings have the same temperature,and if the plate is painted on all surfaces then it is fairly reasonable to assume that the plate will come to thermal equilibrium with the paint surface.
Try googling heat transfer coefficient and cooling zone.com
 
There are some very tricky variables! Many years ago, 3M was making a "Solar-Absorbent" coating that was super-black. My observing partner and I managed to cadge a supply of that material from an engineer at 3M so we could coat all the interior surfaces of our telescopes, adapters, eyepieces, etc with it. We couldn't legally buy it because the solvents were carcinogenic, but we managed to arrange to get an "engineering sample".

That stuff is WAY blacker and more absorbent than conventional paints.
 
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