How Can I Minimize Temperature Drop in Chamber B During Air Transfer?

  • Thread starter Thread starter Margalit
  • Start date Start date
  • Tags Tags
    Cooling
AI Thread Summary
To minimize the temperature drop in chamber B during air transfer from chamber A, solutions must address the thermal dynamics involved in the process. A proposed method involves using a long, large-diameter tube to connect the valve and chamber B, allowing for thermal diffusion to warm the air before it enters chamber B. Insulating chamber B can help, but it will still experience a temperature drop due to gas expansion and pressure changes. Adding thermal mass, such as a water spray or copper wool, may mitigate the temperature decrease by providing a heat source. Overall, effective thermal management is crucial to maintaining temperature stability during rapid air transfers.
Margalit
Messages
4
Reaction score
0
I have a practical problem that I am trying to solve regarding using air chambers. I hope someone can help me with the problem. I have two air chambers connected by a tubing and a valve. One is pumped to a low pressure, chamber A (~30 kPa), and the other is at near atmospheric pressure, chamber B. When I open the valve I get air rushing into chamber A. Once the valve is closed, the remaining air temperature in chamber A is hotter and the air in chamber B is colder. Both started at room temperature. So far this makes sense and I understand the reasons why this occurs.

However, I am looking for a solution to minimize the temperature drop in chamber B while still transferring the same total amount of air (30 L) in the same period of time (2-3 seconds). Any solution to this general problem is welcome.

I also have a specific implementation in mind however that I hope someone can comment if it is logical or illogical. The solution is to have a long tube or relatively large diameter (2 inches) connect between the valve and chamber B. The diameter of the tube will be significantly larger than the opening of the valve (0.5 inches), so there will be very little pressure differential per unit length in the large diameter tube. The idea is that the low temperature will be created at the valve to tube interface. The cold air will be formed at the valve. The long length of the tube will provide the necessary thermal diffusion distance for the air to be heated by the tube walls before the low temperature reaches chamber B. This of coarse only makes sense if the temperature differential is actually forming at the valve itself and not uniformly a long the tube and chamber B.

I am willing to experimentally do this solution, however if someone sees this as flawed logical it could save me a lot of time.

Thanks,

Near
 
Physics news on Phys.org
The temperature of the bulk gas on both sides that is not transferred will be subjected to a change in pressure. That will result in a temperature change. Unless you can thermally couple the non-exchanged volumes of air you will see the change in temperature.

The temperature change on the low pressure side will be due to the bulk pressure increase and the mixing of the cooled air released through the valve. The high pressure side will not have heat energy transferred against the airflow.
 
However, I am looking for a solution to minimize the temperature drop in chamber B while still transferring the same total amount of air (30 L) in the same period of time (2-3 seconds). Any solution to this general problem is welcome.

If the walls of B are insulated then as the gas expands it's temperature must fall. Only solution is to add energy to B somehow.

http://www.etomica.org/app/modules/sites/JouleThomson/Background2.html

Even if the walls of B are good conductors of heat and there is an outside heat source it takes time for energy to move. So that may not stop a short term fall in temperature before it recovers. The thermal time constant of the system may matter.

The gas inside B also has thermal resistance - so even if the gas near the walls of B could be kept at a constant temperature, the temperature of the gas in the middle might fall before recovering.

Scuba divers have the opposite problem. As their tanks are filled they heat up. They put them in water to improve the rate at which heat is lost by a factor of 25 and that helps keep them cool..

http://www.scubadiversions.com/services.htm

We provide all of our gas fills for dive tank cylinders in a refrigerated water bath. Why? Because significant heat is generated when cylinders are filled, and the end result is that you end up with less pressure in the tank after it cools down. Complete immersion in a water bath draws this heat away at a significant rate (25 times faster than an air environment, as you may remember from your scuba diving class). The colder the water is, the more efficient the heat transfer. This not only reduces the time necessary to obtain a full pressure gas fill, it also means that you will have a greater volume of air or gas in your tank.
 
Possible solution might be to partly fill B with a constant water spray or copper wool? Something that would add a distributed thermal mass. It wouldn't stop the temperature dropping totally but might reduce the magnitude of the drop.
 
One chamber could be a large vehicle radiator or heat exchanger radiator, enclosed by a very slightly larger rectangular box chamber. The two chambers would then have both thermal mass and close thermal contact.
 
Thread 'Question about pressure of a liquid'
I am looking at pressure in liquids and I am testing my idea. The vertical tube is 100m, the contraption is filled with water. The vertical tube is very thin(maybe 1mm^2 cross section). The area of the base is ~100m^2. Will he top half be launched in the air if suddenly it cracked?- assuming its light enough. I want to test my idea that if I had a thin long ruber tube that I lifted up, then the pressure at "red lines" will be high and that the $force = pressure * area$ would be massive...
I feel it should be solvable we just need to find a perfect pattern, and there will be a general pattern since the forces acting are based on a single function, so..... you can't actually say it is unsolvable right? Cause imaging 3 bodies actually existed somwhere in this universe then nature isn't gonna wait till we predict it! And yea I have checked in many places that tiny changes cause large changes so it becomes chaos........ but still I just can't accept that it is impossible to solve...
Back
Top