How can I solve a non-quadratic equation with the form y^4+4y-69=0?
Thread starterjustin345
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justin345
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Homework Statement
I have been solving a problem, which turned into this equation. Obviously it is not a quadratic equation. I am a little bit confused how to solve this one?
It's not even an equation, so you can't solve for y. If the equation is y4 + 4y - 69 = 0, about the best you can do is get an approximate solution using a technique such as Newton's Method.
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Hello,
This is the attachment, the steps to solution are pretty clear. I guess there is a mistake on the highlighted part that prompts this thread.
Ought to be ##3^{n+1} (n+2)-6## and not ##3^n(n+2)-6##. Unless i missed something, on another note, i find the first method (induction) better than second one (method of differences).