How Can I Solve for k in the Equation v = d√(k/m)?

Thread starter PhysicsOPhun
Start date Feb 26, 2008

AI Thread Summary

To solve for k in the equation v = d√(k/m), start by squaring both sides to eliminate the square root. This gives v² = d²(k/m). Next, rearrange the equation to isolate k by multiplying both sides by m and dividing by d². The final formula for k becomes k = (v² * m) / d². This method effectively allows for the calculation of k based on the values of v, d, and m.

Feb 26, 2008

PhysicsOPhun

very very very simple question...for you

So if v = d\sqrt{k/m}

how can i turn that into solving for "k"?

Homework Equations

The Attempt at a Solution

Physics news on Phys.org

Feb 26, 2008

CompuChip

Science Advisor

Homework Helper

Well, there is a k under a square root... so what about you start by squaring both sides of the equation?

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...

View full post »

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »