How can I solve this Trigonometry equation in RxR?

  • Thread starter Thread starter Andrax
  • Start date Start date
  • Tags Tags
    Trigonometry
AI Thread Summary
To solve the trigonometric equations sin(3x) = cos(2y) and sin(x + π/3) = cos(y - π/3) in RxR, one approach is to use trigonometric identities to simplify the equations. The attempt to square both sides and convert to cos(2a) did not yield a valid solution, resulting in y = 0, which was incorrect. Utilizing the sine and cosine addition formulas can help in transforming the second equation for further analysis. This method may lead to a more manageable form to solve for x and y. Exploring these identities is crucial for finding the correct solutions in the given range.
Andrax
Messages
117
Reaction score
0

Homework Statement


we have sin(3x)=cos(2y)
sin(x+pi/3)=cos(y-pi/3)
solve in RxR

Homework Equations





The Attempt at a Solution


i tried squaring both sides and turning everything to cos 2a then turning it into an XY=0
but that didn't help at all i ended up with y=0 which turned out to be wrong
 
Physics news on Phys.org
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top