How can Lagrange Identity be used to prove a vector equation?

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The discussion focuses on using the Lagrange Identity to prove the vector equation (A x B) . (u x v) = (a.u)(b.v) - (a.v)(b.u). A participant suggests that the left-hand side can be expressed as a determinant involving the cross products and the vectors u and v. They emphasize the need to calculate the determinant and the right-hand side explicitly to complete the proof. The conversation highlights the importance of hands-on calculations in understanding the proof process. Engaging with the mathematical details is essential for a successful demonstration of the equation.
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Homework Statement



Prove that (A x B) . (u x v) = (a.u) (b.v) - (a.v)(b.u)


The Attempt at a Solution



I've used lagrange indentity to proof that. but I can't go ahead

Thanks
 
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Patience is a virtue here.

I guess you know already that the LHS equals to:
det((AxB)1 (AxB)2 (AxB)3 ; u1 u2 u3 ; v1 v2 v3)

and that (AxB)i= Aj Bk - Ak Bj for a suitable cyclic order.
Now calculate the determinant.

afterward calculate explicitly the RHS.

There's no other way, you need to get your hand dirty.
 
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