# 1-D Lagrange and Hamilton equation gives different results.

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1. May 3, 2016

### 13Nike

1. The problem statement, all variables and given/known data
This was supposed to be an easy question. I have a question here that wants you to describe a yoyo's acceleration (in one dimension) using Lagrangian mechanics. I did and got the right answer. Now I want to use Hamilton's equations of motion but I get a wrong number. Here is the excerpt

"A yoyo attached to a mass less string is suspended vertically from a fixed point and the other end is wrapped several times around a uniform cylinder of mass, m and radius R. When the cylinder is released it moves vertically down, rotating as the string unwinds. Write down the Lagrangian equation using the distance x as your generalized coordinate. Find the Lagrange equation of motion and show that the cylinder accelerates downward with #\ddot{x}# = 2g/3"
2. Relevant equations
I used Hamilton equation xdot = partial H/partial P
To help,
L = (3/4) m xdot^2 + mgx
and
H = (3p^2)/(4m) - mgx

3. The attempt at a solution

I used Hamilton's equation and took the derivative
d/dt (xdot) = xddot = d/dt(3p/4m)
xddot = (3 xddot)/2

2. May 3, 2016

### TSny

The momentum, $p$, that enters into the Hamiltonian should be the "canonical momentum" which is determined from the Lagrangian. You should find that $p \neq m \dot{x}$.

3. May 3, 2016

### 13Nike

I get $p = \partial L / \partial \dot{q} = (6/4) m \dot{x}$ but I dont know how/where to replace this $p$ into. Back into L and then re equate the Hamiltonian then use the Hamiltonian equation?

4. May 3, 2016

### TSny

OK for your result for $p$.

I don't understand what you mean when you say "re equate the Hamiltonian". There is a specific prescription for constructing the Hamiltonian from the Lagrangian and the canonical momentum.

5. May 3, 2016

### 13Nike

We im stuck at $p = (6/4)m \dot{x}$ do I take this result and somehow put $p$ back into the lagrange?

6. May 3, 2016

7. May 3, 2016