How can Lagrange Identity be used to prove a vector equation?

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SUMMARY

The discussion focuses on using Lagrange Identity to prove the vector equation (A x B) . (u x v) = (a.u)(b.v) - (a.v)(b.u). The left-hand side (LHS) is expressed as the determinant of a matrix formed by the cross product (A x B) and vectors u and v. The right-hand side (RHS) requires explicit calculation to verify the equality. Participants emphasize the necessity of hands-on calculation to arrive at the proof.

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Homework Statement



Prove that (A x B) . (u x v) = (a.u) (b.v) - (a.v)(b.u)


The Attempt at a Solution



I've used lagrange indentity to proof that. but I can't go ahead

Thanks
 
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Patience is a virtue here.

I guess you know already that the LHS equals to:
det((AxB)1 (AxB)2 (AxB)3 ; u1 u2 u3 ; v1 v2 v3)

and that (AxB)i= Aj Bk - Ak Bj for a suitable cyclic order.
Now calculate the determinant.

afterward calculate explicitly the RHS.

There's no other way, you need to get your hand dirty.
 

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