I_am_no1
- 17
- 0
v = \epsilontrans/ \epsilonaxial
where
ν is the resulting Poisson's ratio,
\epsilontrans is transverse strain
\epsilonaxial is axial strain
and Poissions Ratio have range and its not more then 0.5 and not less then -1?
so my question is how its value can turn "-1"?
As its already neative and its axial strain or transverse strain one must be negative so the value of Poissions Ratio will turn positive! what do you say!
where
ν is the resulting Poisson's ratio,
\epsilontrans is transverse strain
\epsilonaxial is axial strain
and Poissions Ratio have range and its not more then 0.5 and not less then -1?
so my question is how its value can turn "-1"?
As its already neative and its axial strain or transverse strain one must be negative so the value of Poissions Ratio will turn positive! what do you say!