How can substitution be used to solve a differential equation?

scrtajntman
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Homework Statement


The problem states: Use substitution to solve:

y'=1/(x+y)^2-1

Homework Equations


The Attempt at a Solution



I used the substitution of v=x+y

resulting in the answer y=[3(x-C)]^(1/3) - x

but I'm not too sure that's right

Can some help with the answer and the steps for getting it. It's just for a practice test so I'm not graded on it.
 
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Show all of the steps you took to get the correct answer. If you made an error in any step, we could point it out then.
 
scrtajntman said:

Homework Statement


The problem states: Use substitution to solve:

y'=1/(x+y)^2-1

Homework Equations


The Attempt at a Solution



I used the substitution of v=x+y

resulting in the answer y=[3(x-C)]^(1/3) - x

but I'm not too sure that's right

Can some help with the answer and the steps for getting it. It's just for a practice test so I'm not graded on it.

It looks like you got to (x+y)^3=3x+C correctly (you probably had -3C instead of +C but it makes no difference since both are just undetermined constants) ? ...If so, this is how you should leave your answer (unless you are given a point on the curve y(x)). The reason being is that there are actually three roots to this cubic equation, and y+x=\sqrt[3]{3x+C} is only one of them.
 
Great! So overall I got the problem right. Thanks.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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