How can the effect of air temperature on an object be quantified?

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Discussion Overview

The discussion revolves around quantifying the effect of air temperature on an object, specifically focusing on how long it takes for a cold bottle of water to reach a certain temperature in a warm room. Participants explore theoretical approaches, formulas, and the complexities involved in heat transfer between the air and the object.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant inquires about the possibility of calculating the time for water to reach a certain temperature and asks for relevant formulas.
  • Another participant notes that the heat transfer depends on the bottle's placement and shape, mentioning the importance of the surface-to-volume ratio and introducing the concept of a thermal flux coefficient.
  • There is a discussion about the local heat flux density and material conductivity, with a participant seeking clarification on the relationship between these concepts and the thermal flux coefficient.
  • One participant suggests that the solution to the heat transfer problem could involve a differential equation and mentions that the resulting function would be exponential.
  • Another participant proposes a model using electrical components to analogize the thermal process, comparing the current through a resistor to thermal flux.
  • Concerns are raised about the complexity of the problem, particularly regarding temperature distribution within the bottle as the water heats up.
  • One participant expresses a belief that there should be a maximum energy transfer rate from the air to the object, suggesting that this could be a constant, but admits to struggling to find relevant information.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the exact formulas or methods to quantify the heat transfer, and multiple competing views on the complexity and modeling of the problem remain. The discussion reflects uncertainty and varying interpretations of the concepts involved.

Contextual Notes

Participants acknowledge limitations in their understanding of the heat transfer process, including the need for specific assumptions about the bottle's properties and the conditions of the environment. There is also mention of unresolved mathematical steps in deriving the necessary equations.

PytrTchaikovsky
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Let's say I have a cold bottle of water in a warm room (temperature is constant). Is it possible to calculate how long it will take for the water to reach a certain temperature? Do you guys know any formula for this? To be more general:

What is the effect (W, J/s) that air in a certain temperature give an object surrounded by the air?
 
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PytrTchaikovsky said:
What is the effect (W, J/s) that air in a certain temperature give an object surrounded by the air?
Yes, that's the big question. That depends of how the bottle is placed ( hanging in a wire / placed on a table ) and the shape of the bottle ( the relation: surface / volume is important ). This thermal flux coefficient is calculated with [ W/ΔTemperature ] as unit.

Having found the thermal flux coefficient, you can make a differential equation.
 
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Hesch said:
Yes, that's the big question. That depends of how the bottle is placed ( hanging in a wire / placed on a table ) and the shape of the bottle ( the relation: surface / volume is important ). This thermal flux coefficient is calculated with [ W/ΔTemperature ] as unit.

Having found the thermal flux coefficient, you can make a differential equation.

Thank you very much. Damn this is complex. Thought it would be like putting water on the stove and calculating when it will boil. Is it possble to calculate all of this theoretically, without experimenting? Are there any formulas out there? Tried looking all this up on Wikipedia, found this:

98008b679d74c27307d86640314e0878.png


151402b443097619f039039bd77bc675.png
is the local heat flux density, W·m−2,
ec2aa8ec0ee0f525bcf413c9fd8e87e9.png
is the material's conductivity, W·m−1·K−1,
c29d7b28f7486d0388b856afd85ddd30.png
is the temperature gradient, K·m−1.

Is this
151402b443097619f039039bd77bc675.png
the thermal flux coefficient you mentioned? Note that the "m" in the explanation above isn't mass, it is meters. How do I apply a distance to my water? How can I take this further to calculate the time it takes to heat the water?

Thanks
 
PytrTchaikovsky said:
Is this
p?image=https%3A%2F%2Fupload.wikimedia.org%2Fmath%2F1%2F5%2F1%2F151402b443097619f039039bd77bc675.png
the thermal flux coefficient you mentioned?
No, that's the flux density [ W/m2].
I would say that k [ W/(K*m)] is closer. Actually the unit is [ (W*m)/(K*m2 ) ], meaning that k*area/thickness [ W/K ] gives the "thermal flux coefficient". ( I think it's a term of my own? ). You can also call it "the specific thermal conductiviy" for a material.
PytrTchaikovsky said:
Are there any formulas out there?
No, but there are some "rule of thumb":
If you have a black copper plate, about 3mm thick and mounted vertically, the thermal resistance will be θ = 600/A [ K/W ], where A is its area in cm2. But I don't think your bottle is black, and it's not made of copper.
PytrTchaikovsky said:
How can I take this further to calculate the time it takes to heat the water?
You must make some differential equation, modelling your bottle containing water. The solution to the equation will be an exponential function. Isolate t (time) in an equation.

You may make a model by connecting a resistor and a capacitor in series and then charge the capacitor through the resistor. The current through the resistor is similar to the thermal flux, the voltage drop across the resistor is the temperature difference between air and bottle, the capacitor voltage is the temperature of the bottle.

The bottle is a difficult problem because when the air heats up the water, the warm water will be gathered at the top of the bottle and vica versa. So speaking of temperature of the water, you could ask: Where in the bottle?
 
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Hesch said:
No, that's the flux density [ W/m2].
I would say that k [ W/(K*m)] is closer. Actually the unit is [ (W*m)/(K*m2 ) ], meaning that k*area/thickness [ W/K ] gives the "thermal flux coefficient". ( I think it's a term of my own? ). You can also call it "the specific thermal conductiviy" for a material.

No, but there are some "rule of thumb":
If you have a black copper plate, about 3mm thick and mounted vertically, the thermal resistance will be θ = 600/A [ K/W ], where A is its area in cm2. But I don't think your bottle is black, and it's not made of copper.

You must make some differential equation, modelling your bottle containing water. The solution to the equation will be an exponential function. Isolate t (time) in an equation.

You may make a model by connecting a resistor and a capacitor in series and then charge the capacitor through the resistor. The current through the resistor is similar to the thermal flux, the voltage drop across the resistor is the temperature difference between air and bottle, the capacitor voltage is the temperature of the bottle.

The bottle is a difficult problem because when the air heats up the water, the warm water will be gathered at the top of the bottle and vica versa. So speaking of temperature of the water, you could ask: Where in the bottle?

Found this lecture from MIT, touched the subject a little, but went more to chemistry.
http://ocw.mit.edu/courses/chemistr...-state-of-a-system-0th-law-equation-of-state/

Also: I feel like air of a certain temperature higher than an object should have a maximum amount of energy that it can give that object during a certain time, joules per second, W. Then as you say, the object may have certain proporities that make it less able to absorb that energy. But, that maximum W of the air of a certain temperature compared to the object, should be some sort of constant according to me. Been searching all over to find something, but does not really seem to find anyting of value.

Thank you again, if you find more helpful information i will be glad. Will try to fix a equation of some sort.
 
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