How Can the Integral of 1/sqrt(x^2 - 1) Be Expressed Using Ln?

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Homework Statement



[tex]\int[/tex]dx/[tex]\sqrt{}x^2 -1[/tex]
I actually know that the answer is arccosh(x) but I want to prove it in form of Ln(x+[tex]\sqrt{}x^2 -1[/tex])

Homework Equations


The Attempt at a Solution


I have tried many times such as u=x2-1 and u=x2
 
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Did you mean ...

[tex]\int\frac{dx}{\sqrt{x^2-1}}[/tex]