How Can Trigonometric Substitution Simplify the Integral of x²/√(1-x²)?

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Homework Help Overview

The problem involves evaluating the integral of x² divided by the square root of (1 - x²) from 0 to 1, suggesting a context within calculus and integral evaluation, particularly focusing on trigonometric substitution techniques.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the substitution of x with sin(theta) and the corresponding differential dx. There is mention of using trigonometric identities to simplify sin²(theta) and the need to express the integral correctly with the substitution in place.

Discussion Status

Some participants have provided guidance on using trigonometric identities and substitution, while others are exploring different expressions for sin²(theta). Multiple interpretations of the substitution process are being examined, but there is no explicit consensus on the next steps.

Contextual Notes

There is a noted absence of the differential dx in the original integral, which participants are addressing. The discussion also reflects on the need for clarity in the substitution process and the implications of using trigonometric identities.

kathrynag
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Homework Statement



[tex]\int^{0}_{1}\frac{x^{2}}{\sqrt{1-x^{2}}}[/tex]

Homework Equations





The Attempt at a Solution


Let x=sintheta
dx=cos theta
[tex]\int^{0}_{1}\sin^{2}[/tex]
Now I get stuck
 
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well, i believe

[tex]sin^2x=\frac{1-cos2x}{2}[/tex] would help.
 
You don't show dx in your original integral, but it should be there. You need to replace it and the square root in the denominator, using your substitution.

In your substitution, dx = cos(theta) d(theta).
 
There's a trig formula that let's you express sin(theta)^2 in terms of cos(2*theta). Can you find it?
 
sutupidmath said:
well, i believe

[tex]sin^2x=\frac{1-cos2x}{2}[/tex] would help.

so then i would make u=2x and du=2dx
 
kathrynag said:
so then i would make u=2x and du=2dx

well first you would break it into 1/2-1/2 cos(2x) then if you want you can make that substituion, that would work.
 
sutupidmath said:
well first you would break it into 1/2-1/2 cos(2x) then if you want you can make that substituion, that would work.

Ok, well that's what I meant.
 
:wink:
kathrynag said:
Ok, well that's what I meant.
 

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