How Can We Rewrite the Limit and Continuity Equation Lim(x-->0) x/a[b/x]?

[Kartik.]

Lim(x-->0) x/a[b/x] can be written as x/a(b/x-{b/x})

how can we write this as
lim(x-->0)
(b/x -b/a({b/x}/{b/x}))?

 

[CompuChip]

Do [square] and {curly} brackets have some special meaning to you? Because
\lim_{x \to 0} \frac{a}{x} \frac{b}{x} \neq \frac{x}{a} \left( \frac{b}{x} - \frac{b}{x} \right)
doesn't really make sense to me.

 

[Kartik.]

Do [square] and {curly} brackets have some special meaning to you? Because
\lim_{x \to 0} \frac{a}{x} \frac{b}{x} \neq \frac{x}{a} \left( \frac{b}{x} - \frac{b}{x} \right)
doesn't really make sense to me.

Sorry, they are very common in my exercise books
square brackets mean the greatest integer value of the variable within and the curly brackets mean the fractional part of the variable within.

 

[mathman]

Lim(x-->0) x/a[b/x] can be written as x/a(b/x-{b/x})

how can we write this as
lim(x-->0)
(b/x -b/a({b/x}/{b/x}))?

Your question is a little confusing. You have a term {b/x}/{b/x} (=1??). So it seems you are asking about (b/x - b/a)?