How can you accurately calculate fault current on a finite bus by hand?

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SUMMARY

This discussion focuses on calculating fault current (FC) on a finite bus, specifically using a 225 KVA transformer with a 5% impedance and a voltage transformation from 480V to 208V. The participant highlights the difference in fault current calculations between an infinite bus and a finite bus, noting that while 12491A is available on the secondary, the primary current is calculated to be 5412.8A. The key takeaway is that the source must supply the required current, emphasizing the principle of power conservation: power in equals power out.

PREREQUISITES
  • Understanding of transformer ratings and impedance (e.g., 225 KVA transformer with 5% impedance)
  • Knowledge of three-phase power systems and voltage transformation (e.g., 480V to 208V)
  • Familiarity with fault current calculations and their significance in power systems
  • Basic principles of Ohm's Law and power conservation in electrical circuits
NEXT STEPS
  • Research fault current calculation methods for finite bus systems
  • Explore the use of SKM PowerTools for fault analysis in electrical systems
  • Study the implications of transformer impedance on fault current levels
  • Learn about the differences between infinite and finite bus systems in power engineering
USEFUL FOR

Electrical engineers, power system analysts, and students studying transformer operations and fault current calculations will benefit from this discussion.

danielandham
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so calculating FC on an infinite bus is easy but how do you calculate it by hand for a finite bus?

here is the concept i am having an issue understanding:

let say i have a transformer that is 225KVA with 5%z and 3 phase 480 to 208.

with infinite bus i have 12491A available on the secondary of this transformer IF 12291A is flowing on the secondary then based on the voltage ratio and OHMs law 5412.8 A is flowing on the primary.

If this is true then what does it matter if i have infinite amps available on the primary or i have 5412.9 amps available 12491A should still flow in my mind.

I have run this in SKM and i see that it does matter but i just don't understand why.
 
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Let's talk in an ideal world. If you have no load, no current will flow. As you add a load to the secondary, current will flow based on the secondary voltage. Since power in == power out, then equal power will flow in the primary and you can calculate the primary current based on the primary voltage. So the key is power in == power out. Your source merely needs to be able to supply the required current.

I'm not sure where ohms law comes in since you aren't talking resistance yet. I don't quite understand your infinite vs finite either. Am I missing some basic assumption?
 

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