How Can You Accurately Draw the Riemann Xi Function Curve?

  • Thread starter Thread starter zetafunction
  • Start date Start date
  • Tags Tags
    Curve
zetafunction
Messages
371
Reaction score
0
how to draw this curve ??

Arg\xi (1/2+iz)

however i am a bit ashamed because the Riemann Xi function is real for real 'z' so for ALL the real numbers the argument of the \xi(1/2+iz) should be 0 ¡¡
 
Physics news on Phys.org


http://www.wolframalpha.com/input/?i=plot+1%2f2(1%2f2%2bI+z)((1%2f2%2bI+z)-1)Gamma((1%2f2%2bI+z)%2f2)%2fPi^((1%2f2%2bI+z)%2f2)Zeta((1%2f2%2bI+z))&incParTime=true

In the graph in the middle you can barely see the hint of the orange horizontal line for the complex part that is lying on the x axis.
 


thanks a lot Bill... :)
 
##\textbf{Exercise 10}:## I came across the following solution online: Questions: 1. When the author states in "that ring (not sure if he is referring to ##R## or ##R/\mathfrak{p}##, but I am guessing the later) ##x_n x_{n+1}=0## for all odd $n$ and ##x_{n+1}## is invertible, so that ##x_n=0##" 2. How does ##x_nx_{n+1}=0## implies that ##x_{n+1}## is invertible and ##x_n=0##. I mean if the quotient ring ##R/\mathfrak{p}## is an integral domain, and ##x_{n+1}## is invertible then...
The following are taken from the two sources, 1) from this online page and the book An Introduction to Module Theory by: Ibrahim Assem, Flavio U. Coelho. In the Abelian Categories chapter in the module theory text on page 157, right after presenting IV.2.21 Definition, the authors states "Image and coimage may or may not exist, but if they do, then they are unique up to isomorphism (because so are kernels and cokernels). Also in the reference url page above, the authors present two...
When decomposing a representation ##\rho## of a finite group ##G## into irreducible representations, we can find the number of times the representation contains a particular irrep ##\rho_0## through the character inner product $$ \langle \chi, \chi_0\rangle = \frac{1}{|G|} \sum_{g\in G} \chi(g) \chi_0(g)^*$$ where ##\chi## and ##\chi_0## are the characters of ##\rho## and ##\rho_0##, respectively. Since all group elements in the same conjugacy class have the same characters, this may be...
Back
Top