How Can You Apply the Superposition Theorem Graphically?

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The discussion revolves around understanding the superposition principle in circuit analysis rather than just solving a specific problem. Participants emphasize the need to graphically apply superposition by replacing voltage sources with shorts and analyzing the resulting circuits. There is a debate about the necessity of numerical values for circuit analysis, with some arguing that qualitative analysis is still possible. Confusion arises regarding the graphical representation of the circuit and the union of different drawings. Ultimately, the focus remains on effectively applying the superposition principle to understand circuit dynamics.
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I'm trying solve this scheme:

attachment.php?attachmentid=70441&stc=1&d=1402248289.png


but not with the ideia of solve it but yes with the ideia of understand the dynamic of the thing...

aftwer watch this video:


and read about the superposition:
http://en.wikipedia.org/wiki/Superposition_theorem

I did this scheme for solve the problem:
attachment.php?attachmentid=70470&stc=1&d=1402348364.png

attachment.php?attachmentid=70471&stc=1&d=1402348364.png


But, and now, how make the graphical superposition?
 

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Why did you start a second thread about the same problem?
 
dauto said:
Why did you start a second thread about the same problem?

The *same example*, but *different questions*. Here I'm asking about how to construct the equivalent superpostion from of two given. Can you help me?
 
Do what it says in Wikipedia. Replace all but one of the voltage sources with a short. Solve for the case of the solitary source. Repeat for the other source and then add the solutions together.
 
Born2bwire said:
Do what it says in Wikipedia. Replace all but one of the voltage sources with a short. Solve for the case of the solitary source. Repeat for the other source and then add the solutions together.

My friend, is not possbile to solve this problem cause it haven't none numerical value, the better interpretation possible is the which I drew and I'm asking how would the union those two drawings.
 
I have no idea what those drawings are trying to represent but any talk of their "union" is nonsensical. The circuit does not need numerical values to analyze. One could solve it explicitly for the unknown variables as messy as that would be. Actually, after a quick glance it is a simpler matter. In the first case, removing the source between BD results in shorting out R5 and R4, leaving you with a simple circuit of three resistors. Regretfully, the second case does not reduce the number of unknowns but it is a matter of bookkeeping.
 
You don't have ideia because you didn't watch the video... I don't want to solve the system, what I want is apply graphically the superposition principle!
 

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Jhenrique said:
You don't have ideia because you didn't watch the video... I don't want to solve the system, what I want is apply graphically the superposition principle!


This isn't useful. You do not know the nodal voltages without solving the circuit. Heck, there is no reason why you can't have negative voltages too. As such, you have no way of knowing what the relative voltage "heights" are. There is no point in using this representation outside of trying to explain voltage with the classic pressure analogy.
 
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