How Can You Calculate the Energy Content of Waste Steam in Industrial Processes?

AI Thread Summary
To calculate the energy content of waste steam in industrial processes, focus on the mass of steam produced and its latent heat of vaporization, which is approximately 2200 kJ/kg. The drying process generates 16,000 liters of steam over 40 hours at a constant temperature of 160°C. Velocity and pressure are less critical unless they are extremely high, as the primary energy recovery comes from condensing the steam. Using a shell and tube heat exchanger can effectively capture this energy, even if it converts steam back to water. Understanding these factors will help optimize the energy recovery from the waste steam.
vespak
Messages
6
Reaction score
0
I don't know if anyone can help but I have a friend who wants to capture his waste steam and convert it to energy - that's the easy bit - the difficulty is how to work out how much energy he has in the first place. He is drying wood by heating a container to 160oC over a period of approx 40 hours which produces 16,000 litres of water in the form of steam. That exits the container (2.4 x 2.4 x 6m) through a 400mm flue. In order to capture this I want to put a shell and tube heat exchanger in the flue (I don't mind if this converts the steam back to water, we have another use for that) In order to make this work effectively I need to know what the likely pressure and or velocity does the steam emerge at. I appreciate that there will be a gradual build up in pressure. Its the last 24 hours I am interested in where there is a constant temperature and so presumably a reasonably constant velocity. We already know the saturated steam heat is around 120oC. The only motive power causing the steam to exit the container is the expansion of the air & water vapour/steam inside the container. Fans circulate the heated air inside the container and the flue is sited at the base of the container half way up its length. Any thoughts?
 
Last edited:
Engineering news on Phys.org
Welcome to PF.

You don't really need velocity and even the pressure isn't all that important unless it is very high. The vast majority of the energy to be recovered comes from condensing the steam unless you can cool it well below boiling temp, so by multiplying the mass of steam by the latent heat of vaporization of 2200 kJ/kg you get yourself in the ballpark.
 
Many thanks that's got me going in the right direction.
 
Hi all, I have a question. So from the derivation of the Isentropic process relationship PV^gamma = constant, there is a step dW = PdV, which can only be said for quasi-equilibrium (or reversible) processes. As such I believe PV^gamma = constant (and the family of equations) should not be applicable to just adiabatic processes? Ie, it should be applicable only for adiabatic + reversible = isentropic processes? However, I've seen couple of online notes/books, and...
Thread 'How can I find the cleanout for my building drain?'
I am a long distance truck driver, but I recently completed a plumbing program with Stratford Career Institute. In the chapter of my textbook Repairing DWV Systems, the author says that if there is a clog in the building drain, one can clear out the clog by using a snake augur or maybe some other type of tool into the cleanout for the building drain. The author said that the cleanout for the building drain is usually near the stack. I live in a duplex townhouse. Just out of curiosity, I...
I have an engine that uses a dry sump oiling system. The oil collection pan has three AN fittings to use for scavenging. Two of the fittings are approximately on the same level, the third is about 1/2 to 3/4 inch higher than the other two. The system ran for years with no problem using a three stage pump (one pressure and two scavenge stages). The two scavenge stages were connected at times to any two of the three AN fittings on the tank. Recently I tried an upgrade to a four stage pump...
Back
Top