How can you determine y's behavior from a direction field graph?

Click For Summary
SUMMARY

The discussion centers on analyzing the behavior of the differential equation y' = 3 + 2y using a direction field graph. The equilibrium position is identified at y = -3/2, where the slope of the graph is zero, indicating stability at this point. The participants clarify that while the graph shows behavior at y = -3/2, it is essential to examine the direction field for values of y greater than or less than -3/2 to understand the overall behavior of y as t approaches infinity. The conclusion emphasizes that the initial value of y significantly influences its trajectory over time.

PREREQUISITES
  • Understanding of differential equations, specifically first-order linear equations.
  • Familiarity with direction field graphs and their interpretation.
  • Knowledge of equilibrium points and their significance in dynamical systems.
  • Basic calculus concepts, including limits and behavior of functions as variables approach infinity.
NEXT STEPS
  • Explore the stability of equilibrium points in differential equations.
  • Learn how to construct and interpret direction field graphs for various differential equations.
  • Investigate the behavior of solutions to first-order linear differential equations using initial value problems.
  • Study the concept of phase portraits and their applications in dynamical systems.
USEFUL FOR

Students and educators in mathematics, particularly those studying differential equations, as well as researchers and professionals analyzing dynamical systems and their behaviors.

dwilmer
Messages
11
Reaction score
0
How can you determine y's behavior from a direction field graph??

lets say i have the equation y' = 3 + 2y and i make a direction field graph.

I find equilibrium position at y = -3/2.

If question asks me to determine behavior of y as t approaches infinity, isn't this impossible, without solving the equation?

If i follow along the graph so that t is really big, then the graph still looks the same: a horizontal line at y = -3/2, where the slope of graph is zero. So how can i infer anything about y's behavior without first solving for y?
 
Physics news on Phys.org


No, the graph is NOT "a horizontal line at y= -3/2". That line is a part of the direction field graph and you can conclude from it that "if y= -3/2 for any t then it will remain -3/2 for all t". But what if the initial value of y is NOT -3/2?

What does the direction field graph look like for y> -3/2? If y(0)> -3/2, what happens to y(t)?

What does the direction field look like for y< -3/2? If y(0)< -3/2, what happens to y(t)?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
9K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K