How Can You Simplify This Limit Calculation in Calculus?

[gohar]

simple prob...pls solve

Plz some one explan How...


lim x->1 [ 1 / 1-x - 3 / 1-x^2 ] = lim x->1 [1+x-3 /1-x^2]

 

[lkh1986]

I think you should put the terms in bracket so that we can understand which numerator belongs to which denominator. It's quite hard to see it like this.

 

[cristo]

Well, here you are asked to simplify \frac{1}{(1-x)}-\frac{3}{(1-x^2)}=\frac{1}{(1-x)}-\frac{3}{(1+x)(1-x)}

There's a hint, but please note we cannot do your homework for you; you must attempt it first!

Edit: As lkh1986 says, it would be clearer to bracket it. (However, it's clear that the expression I wrote above is correct).

 

[gohar]

Thanks cristo.....i know this step please do one step more...

 

[cristo]

How about you try the next (and last) step, and I'll help you if you get stuck- I'm not going to do it for you!

What do you need to multiply the left hand term by in order to make the denominator 1-x^2?