How Can You Solve the Equation (U2-U1)=259.2(U2*U1) with Two Unknowns?

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The equation (U2-U1)=259.2(U2*U1) features two unknowns, U1 and U2, making it impossible to find a unique solution. A suggested approach involves using the ratio U2/U1, which can be expressed as x, leading to a quadratic equation x^2-259.2x-1=0. The constant 259.2 relates to the context of drag and speed reduction, indicating that understanding the ratio can help determine the difference U2-U1. While the equation has multiple solutions forming a hyperbola, knowing one variable allows for the calculation of the other. The discussion highlights the importance of context in solving such equations.
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Hi

I have the following equation:

(U2-U1)=259.2(U2*U1)

Both U1 and U2 are unknowns. Its been suggested to use an iterative process like Newton Raphson to solve but all examples using this technique are only for one unknown.

(U2-U1) is the value of interest.

Thanks
 
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You have 1 equation with 2 unknowns.
There is no single solution for that.

If you want a solution, you can take U1=0 and U2=0.

The set of all solutions is a hyperbola.
 
Sometimes it is possible to solve these types of equation if we know what U1 and U2 refer to.

For instance if they are sides of a rectangle and there is some area restriction.

Another case (coupled chemical reactions) is solved in posts 57 - 61 of this thread

https://www.physicsforums.com/showthread.php?t=398208&highlight=seawater

go well
 
skaboy607 said:
(U2-U1) is the value of interest.

Thanks

I don't see a way to solve for the difference between the variables, but you can solve for the ratio of them U2/U1.

U2/U1-U1/U2=259.2

Let x=U2/U1

x-1/x=259.2

x^2-259.2x-1=0

Now you can solve the quadratic.
 
Last edited:
Its an equation for drag that has been reduced to its current format. The constant 259.2 comes from the delta t. I need to find how much the speed drops by, i.e. delta U.
 
skaboy607 said:
I need to find how much the speed drops by, i.e. delta U.

The ratio U2/U1 could be considered a measure of how much the speed drops by. And, once you know one value (either U2 or U1) you can calculate the other and identify U2-U1.
 
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