How Can You Solve the Homework Challenge on Vectors and Similar Triangles?

AI Thread Summary
The discussion focuses on solving a homework problem involving vectors and similar triangles. A key point is the justification for stating that segment PQ is half the length of segment SR, which is based on Q being the midpoint of OR and the parallelism between PQ and SR. The similarity of triangles OPQ and OSR is emphasized, confirming that point P is the midpoint of OS. Additionally, there is a note on the correct notation for the triangles, advising against using the Δ symbol for the quadrilateral PQRS. Overall, the conversation provides insights into geometric relationships and proper notation in mathematical problems.
LiHJ
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Homework Statement



Dear Mentors and PF Helpers,

Here's the question:

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Homework Equations

The Attempt at a Solution



Here's my solutions:

Please let me know whether I'm right. Thank you

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Hi LiHJ. How would you justify saying PQ is half the length of SR?

Edit: the rest looks right, though you are a bit rough & ready with the geometry. PQRS shouldn't be designated using the Δ symbol! :)
 
Because the question mention that Q is the midpoint of OR and PQ is parallel to SR. So triangle OPQ is similar to triangle OSR. Therefore P is a midpoint of OS
 
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Thank you;)
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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