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How charge acceleration is dependent on radiation of electromagnetic wave?

  1. Apr 17, 2012 #1
    Is there any mathematical relation between the value of charge(ie proton/electron) and radiation which is being emitted? I m sure energy is conserved in this process so does that mean electron decelerates in process of radiation ?
     
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  3. Apr 17, 2012 #2

    mfb

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    Radiation which is emitted where?
    If you have a particle with a larger charge (but otherwise identical), you can expect that it radiates more photons than another particle.

    Energy conservation is a completely different area.

    Deceleration is the same as acceleration (in terms of "increases absolute velocity"), just for different observers.

    A free electron cannot emit a real photon without violating energy or momentum conservation. However, it can exchange virtual photons or emit real photons if more particles are involved in the process.
     
  4. Apr 17, 2012 #3
    Well I've read that a accelerated charge releases EM wave..By doing so,charge loses its energy right? Which inturn results in decrease of velocity(deceleration as I meant)..So whats the relation which holds with energy released in this process and amount of acceleration..Hope u get my claim..THanking you
     
  5. Apr 17, 2012 #4

    mfb

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    I think you mean synchrotron radiation. Yes, accelerated electrons can radiate away energy and therefore become slower (more important: less energetic).
     
  6. Apr 20, 2012 #5
    Does this mean violation of conservation of energy..?!?!!
     
  7. Apr 20, 2012 #6

    mfb

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    No, it means that a free electron does not emit a real photon.
    Note that an electron in an electromagnetic field is not free, but can interact with other photons. The process "electron+photon -> electron+photon with different momenta" is possible.
     
  8. Apr 20, 2012 #7
    The electron can be accelerated (decelerated) either transversely (synchrotron radiation) or longitudinally. Whenever there is acceleration, there is radiation. The rate of energy loss is
    [tex] \frac{dW}{dt}=-\frac{e^{2} \dot{v}^2}{6\pi\epsilon_o c^3} [/tex] where [itex] \dot{v} [/itex] is the acceleration.
     
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