How Close Must You Stand to Not Hear Sound from Two Separated Speakers?

  • Thread starter Thread starter bio.student24
  • Start date Start date
  • Tags Tags
    Sound
AI Thread Summary
To determine how close a person can stand to speaker A without hearing sound from two separated speakers, the problem involves calculating the point of destructive interference. The speakers are 1.00 m apart, and the wavelength of the sound is 0.800 m. For destructive interference to occur, the path length difference must equal half the wavelength, which is 0.4 m. By applying the Pythagorean theorem to find the distances from the person to each speaker, the solution yields a distance of 1.05 m from speaker A. This calculation confirms the closest distance where sound cancellation occurs.
bio.student24
Messages
11
Reaction score
0
PLEASE HELP! Speakers and Sound--- simple problem!

Two radio speakers produce sound with a wavelength of 0.800 m. If the two speakers are separated by 1.00 m as shown in the diagram, how close to speaker A can a person stand and not hear the sound they produce?

DIAGRAM:

[A] --------d---------- person
|
|
|


where [A] and are the speakers (they are 1.00 m apart)

The answer is d=1.05m

How do i solve this problem?

i know that in order not to hear sound, it must be destructive interference, so when the wavelengths reach the person, they must be out of phase = [m + 0.5(lambda)] where m=0,1,2...

I don't know what kind of formula to use... please help! :(
 
Physics news on Phys.org


For destructive interference, the path length difference from the sources to the person must be λ/2, or 3λ/2 or 5λ/2 or any odd number multiplied by λ/2. Here you want the closest distance the person can be, so the path length difference must be λ/2. Can you find the path length difference?
 


Path length difference = λ/2 = 0.8/2 = 0.4 m

But now what would I do?
 


I'm not sure if this is the 'correct' method... but if i use a2 + b2 = c2

then 12 + x2 = (x+0.4)2
1 - 0.8x -0.16 = 0
x= 0.84/0.8 = 1.05 m
 


bio.student24 said:
I'm not sure if this is the 'correct' method... but if i use a2 + b2 = c2

then 12 + x2 = (x+0.4)2
1 - 0.8x -0.16 = 0
x= 0.84/0.8 = 1.05 m
If L1 is the distance from the person to the closest speaker and L2 is the distance to the farthest speaker, then the path length difference is L2 - L1. Can you find expressions for L1 and L2 in terms of the given quantities and according to the drawing you have posted?
 


hmmm... I've been trying but i can't think of something that works.. :(
 


bio.student24 said:
hmmm... I've been trying but i can't think of something that works.. :(
In your drawing you have a triangle marked by the vertices "a", "b" and "person". Which side should be labeled L1 and which side should be labeled L2?
 


L2 should be the distance between speaker b and the person.
L1 should be the distance between speak a and the person.
right? now what?
 


Back to my earlier posting.

kuruman said:
If L1 is the distance from the person to the closest speaker and L2 is the distance to the farthest speaker, then the path length difference is L2 - L1. Can you find expressions for L1 and L2 in terms of the given quantities and according to the drawing you have posted?
 
  • #10


the only thing i can think of is using Pythagorean theorem for this question..

is there a specific formula or expression relating sound waves and path length difference? i don't know one...
 
  • #11


Use the Pythagorean theorem and find the difference between the two lengths. That difference should be set equal to half a wavelength. Solve the equation to find d.
 
  • #12


thats exactly what i did? haha
thanks :P
 
  • #13


So what's the answer?
 
  • #14


d= 1.05 m
 
Back
Top