How could I figure out the integral of this function

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afcwestwarrior
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Homework Statement



(1-u^2)/(sqrt u)
 
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Go ahead and divide it: (1- u2)/(sqrt(u))= 1/sqrt(u)- u2/sqrt(u)= 1/(u1/2)- u2/u1/2= u0-1/2- u2-1/2=
u-1/2- u3/2.
 
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