# How did they find this angle?

• Engineering

## Homework Statement:

How did they get all the angle here in this problem
Except for the angle 65° which is given it's not stated on how they got it so im having a hard time to understand the problem

## Relevant Equations:

Find angle

Related Engineering and Comp Sci Homework Help News on Phys.org
BvU
Homework Helper
2019 Award
Homework Statement:: How did they get all the angle here in this problem
That's a statement of your problem, not of the homework problem.
Provide a complete problem statement
given:​
knowns:​
unknowns:​

im having a hard time to understand the problem
This way, so am I !

##C## doesn't exist ?

Hi,

So I am slightly confused by some of the lettering, but perhaps I am missing something. If you are told that $\angle BON = 65$, then do you understand the working to find $\angle AOC = 30 degrees$ (I am assuming point C is where point N is)?

If we can accept that, then I think the easiest way to get $\angle BOA$ is just to consider $\angle BON = \angle BOA + \angle AON$. Solving this yields the same answer of 35 degrees.

I believe they have labeled the 115 degrees by using the fact that line segments BA and ON are parallel and $\angle OBA$ and $\angle BON$ are therefore supplementary ('internal' angles of parallel lines add up to 180 degrees), so they could get 115 from $\angle OBA = 180 - 115$

Hope that answers your question. If not, let me know and I will respond appropriately.

Kind regards

BvU
Homework Helper
2019 Award
If not, let me know and I will respond appropriately.
Post the complete problem statement !

Hi,

So I am slightly confused by some of the lettering, but perhaps I am missing something. If you are told that $\angle BON = 65$, then do you understand the working to find $\angle AOC = 30 degrees$ (I am assuming point C is where point N is)?

If we can accept that, then I think the easiest way to get $\angle BOA$ is just to consider $\angle BON = \angle BOA + \angle AON$. Solving this yields the same answer of 35 degrees.

I believe they have labeled the 115 degrees by using the fact that line segments BA and ON are parallel and $\angle OBA$ and $\angle BON$ are therefore supplementary ('internal' angles of parallel lines add up to 180 degrees), so they could get 115 from $\angle OBA = 180 - 115$

Hope that answers your question. If not, let me know and I will respond appropriately.

Kind regards
Thanks for the clarification

Mark44
Mentor

BvU