How do angles of waterwheel affect angular velocity

AI Thread Summary
The angle of the paddles in an undershot waterwheel significantly affects its efficiency in capturing energy from flowing water, rather than its angular velocity directly. As the paddle angle increases from zero, it introduces a larger side loading on the wheel's bearings, which can lead to energy loss. This side loading occurs because an angled paddle deflects the water force, similar to how a tilted oar behaves in rowing. While the angle does not factor into power or efficiency calculations directly, it can lead to wasted energy due to inefficient force application. Understanding these dynamics is crucial for optimizing waterwheel design and performance.
DanielTsai999
Messages
4
Reaction score
0
Hello, I'm currently writing a high school academic paper on waterwheels. One of the things I want to find out is whether the angle of paddles of the undershot waterwheel affects the angular velocity.
So here is my question:
How do the different angles of the paddles in a waterwheel affect it's angular velocity, and why?
Thanks
 
Physics news on Phys.org
Hi. I'm not quite sure what you mean by the question. A paddle has no angular velocity unto itself, since it is a rigid structural component of the wheel. Do you mean how the angle affects the efficiency of capturing energy from the water?
 
Danger said:
Hi. I'm not quite sure what you mean by the question. A paddle has no angular velocity unto itself, since it is a rigid structural component of the wheel. Do you mean how the angle affects the efficiency of capturing energy from the water?
Oooops! Thats what I mean. I'm still kinda new to physics, but I'm guessing it has to do with free body diagrams?
 
Truth be told, young dude, I really have no idea what a "free body diagram" is. We never did any of that kind of stuff when I was in school. I still can't get used to seeing the terms "Newtons" and "bars"; I was taught in foot-pounds, horsepower, and pounds-per-square-inch. (And that was in physics class, not just auto shop.)
What effect the "angle of attack" of the paddle has will partially depend upon how it fits into the overall structure of the wheel. (ie: is it a flow-through design, or does it form an enclosed "bucket" or maybe a "catch-and-release" system..?
I won't be able to provide any meaningful assistance once you get to your exact question, but I hope that perhaps I can help you get to it.
 
Paddle angle does not appear in power or efficiency calculations. As the angle tends away from zero the resultant force has a larger useless component side loading the bearings.
 
Doug Huffman said:
Paddle angle does not appear in power or efficiency calculations. As the angle tends away from zero the resultant force has a larger useless component side loading the bearings.
Side loading? How does that come about? :oldconfused:
 
An angled paddle deflects the force of the water. When you row a boat you want the paddle flat vertical to the water, if you tilt the top in the direction you are rowing the paddle wants to climb out of the water "side loading" the oar pivots.
 
LOL When I was in school we were required to learn in the units of the founder of the field. There has not been, that I know, an error of magnitude caused by mistaking the system of units ETA in my field.
 
Last edited:
Doug Huffman said:
an error of magnitude caused by mistaking the system of units.
The next time they update SI maybe it will be all I use. :-P
 
  • #10
jerromyjon said:
if you tilt the top in the direction you are rowing the paddle wants to climb out of the water "side loading" the oar pivots.
Thank you for that explanation. I had misinterpreted the the term "side" as meaning that it was trying to pull the wheel's shaft out of the housing (so as to need a thrust bearing instead of just a rotary one). Sorry about that.

Doug Huffman said:
ETA in my field.
Oh, great... clear up one question and raise another. :oldgrumpy: Ex-pilot here... in my field, ETA means when you plan to put your ass on the grass. What is it in this context?

In reference to the former, though... how does "useless" enter into it? Doesn't more side-force indicate that more work is being done upon the wheel, and thus giving a greater output? (Or is it a matter of decreasing efficiency as opposed to actual loss?)

edit: Edited the above to add the last sentence.
 
  • #11
Doug Huffman said:
Paddle angle does not appear in power or efficiency calculations. As the angle tends away from zero the resultant force has a larger useless component side loading the bearings.

Yeah, I thought that when the angle of the paddles change, there would be energy wasted. But I have no clue how to calculate that component.
 
  • #12
jerromyjon said:
An angled paddle deflects the force of the water.
But is it possible for me to calculate the force deflected?
 
  • #13
I don't think so because it doesn't just affect the force on the wheel, it also disturbs the flow of the water.
 
Back
Top