How Do Collisions Affect Momentum in Physics Problems?

AI Thread Summary
In the discussion on collisions and momentum, two physics problems are presented involving carts and a skateboard. For the first problem, the final speed of two colliding carts is determined using the conservation of momentum, resulting in a final speed of 4.49 m/s after accounting for their respective masses and initial velocities. It is clarified that the choice of which direction is positive or negative does not affect the outcome, as long as consistency is maintained. The second problem involves a skateboard and a cat, where the skateboard's speed after the cat drops onto it is to be calculated, though specific calculations are not provided. Overall, the importance of applying conservation of momentum principles is emphasized in solving these types of physics problems.
hshphyss
Messages
45
Reaction score
0
Can anyone help me with these two problems? Thank-you

1.) Two carts with masses of 15.5 kg and 6.0 kg, respectively, move in opposite directions on a frictionless horizontal track with speeds of 7.0 m/s and 2.0 m/s, respectively. The carts stick together after colliding head-on. Find the final speed of the two carts.

For this one, I know one of the velocities has to be negative, but which one? Does it matter?

2.) A 1.80 kg skateboard is coasting along the pavement at a speed of 7.0 m/s when a 0.400 kg cat drops from a tree vertically downward onto the skateboard. What is the speed of the skateboard-cat combination.

For this problem I know that the cat's accleration will be -9.8, is that correct?
 
Physics news on Phys.org
hshphyss said:
Can anyone help me with these two problems? Thank-you
1.) Two carts with masses of 15.5 kg and 6.0 kg, respectively, move in opposite directions on a frictionless horizontal track with speeds of 7.0 m/s and 2.0 m/s, respectively. The carts stick together after colliding head-on. Find the final speed of the two carts.
For this one, I know one of the velocities has to be negative, but which one? Does it matter?

I don't believe it matters which direction you choose to be positive and negative, as long as you are consistent throughout the question.

In conservation of momentum, theTotal initial momentium is equal to the total final momentum, and since we are dealing with two bodies, we have

M1V1o + M2V2o = (M1 + M2)Vf
(15.5Kg)(7m/s) + (6.0Kg)(-2m/s) = (21.5Kg)Vf
Vf = 4.49m/s
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top