How Do I Apply Kirchhoff's Loop Law to Solve an H-Bridge Circuit Problem?

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To apply Kirchhoff's Loop Law to an H-Bridge circuit, start by labeling all components clearly, including resistors and currents. Write the Kirchhoff's Voltage Law (KVL) equations for each loop in the circuit, ensuring to account for the direction of current through each resistor. If you have three equations with three unknowns, you can solve them using either substitution or matrix methods, depending on your comfort level with matrices. It may be beneficial to also consider Kirchhoff's Current Law (KCL) for a more intuitive approach. Providing your equations will allow others to offer targeted assistance in solving the circuit problem.
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I am a grade 11 student in Canada. I have an exam in 3 days and i cannot figure out how to solve a cricuit with several loops... i have been told that for this specific cricuit i can use Matricies or Substitution. I don't know anything about Matrices and I am having trouble substituting with three equation and three unknows... i have attached a schematic diagram, it is simalar to a wheatstone bridge and is called an H-bridge. could someone please help me solve this...
 

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Thread moved to the homework forums. Baioff, one of the rules here on the PF is that on homework/exam questions like this, you must show us your work in order for us to help you. Tell us what you do know about writing the KCL or KVL equations. If you write out the equations, it's pretty easy for us to give you some hints on how to solve a set of 3 linear equations in 3 unknowns (if that's what results).
 
Ok srry about that

Homework Statement


circuit attached above... Vt, and all resistances will be given

Homework Equations


Matrix algebra ?

The Attempt at a Solution


well i was shown the following by a physics tutor who was only partially knowlegable on the subject. (resistors labled 1-5 1 being top left 2 top right 3 middle 4 bottom left and 5 bottom right)

0=I2R5+I5R3 - I3R4
0=I4R2+I5R3-I3R4
0=I1R5+I5R3+I6R1 +v

I1=I3+I2
I2+I4+I5
I1=-I5+I6+I4+I5
I3=-I5+I6
I4=I1-I6

then...

I5(R3+R4+R5) =I6R5-I4R5
I5R3=I4R2-I6R1
I5R3=I6(-R5 - R1) -I4R5 - V

I think that's right... but if someone could elaborate on how to decide appon the I number and how they relate to the resistors and possibly an easier way of solving this.
 
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its simple jus assume currents 1 2 3 flowing in threee diff loops
then jus write 3 equations n if a resistor is appearing in 2 circuits take it like
sum of both according to the direction multiplied with resistance which equals voltage
n take net sun of voltages in the loops equal to 0
now for solving the equations u can use matrices or substitution
method which is of ur choice depending on ur ease with the matrices concept
 
First, it would help if you could label the resistors in your sketch. That would make it easier to follow your equations and then suggest ways to reduce the equations.

In addition, are you required to use the KVL loop equations to solve this problem? If not, I find the KCL node voltage equations much more intuitive to work with.
 
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