How Do I Approach a Steady State Current Problem?

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SUMMARY

The discussion centers on solving a steady state current problem in basic electronics. The user correctly identifies that in steady state, inductors behave as short circuits and capacitors as open circuits. They simplify the circuit to a 12V battery connected to a 30-ohm and a 12-ohm resistor in series, calculating the total resistance as 48 ohms, resulting in a steady state current of 0.25A. This conclusion confirms the user's understanding of steady state conditions in DC circuits.

PREREQUISITES
  • Basic understanding of DC circuits
  • Knowledge of Ohm's Law
  • Familiarity with the behavior of inductors and capacitors in steady state
  • Experience with series resistor calculations
NEXT STEPS
  • Study the principles of steady state analysis in electrical circuits
  • Learn about the transient response of inductors and capacitors
  • Explore advanced circuit analysis techniques using Kirchhoff's laws
  • Investigate practical applications of steady state current in real-world circuits
USEFUL FOR

This discussion is beneficial for students studying electronics, particularly those tackling circuit analysis problems involving steady state conditions. It is also useful for educators looking for examples to illustrate these concepts.

Vimto
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Homework Statement


Hello,
I've just done a paper on basic electronics and I'm stuck on the last question. I don't know how to go about doing the question.

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Homework Equations


N/A


The Attempt at a Solution


I don't know how to even start with the question. I've tried googling "steady state current", "steady state current circuit", "how to .." and so on but nothing relevant seems to be coming up. I've also tried to ask my friends who are a year ahead and they can't remember how to do it.
 
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I assume steady state meaning DC which means inductor is a short circuit, it become 0ohm and disappeared. Cap become an open and the 30ohm on the right disappeared. So you only have a 12V battery connecting to a 30ohm and a 12ohm in series which give a total of 48ohm

So the current I=V/R = 12/48=0.25A!

Is this a trick question?
 

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