mjc123 said:Look on the NIST website for Xe, under Fluid properties. The answer for your case is 2015 kg/m3.(There is no general equation like PV = nRT to calculate it.)
Chestermiller said:
n=PVzRT=(15000000)(0.1)(0.40)(8.314)(296.2)=1523 moles=200 kgn=PVzRT=(15000000)(0.1)(0.40)(8.314)(296.2)=1523 moles=200 kg
n=\frac{PV}{zRT}=\frac{(15000000)(0.1)}{(0.40)(8.314)(296.2)}=1523\ moles = 200\ kg So the estimated density is 2000 kg/m3kg/m3kg/m^3.
The density of a super critical fluid can be calculated using the following formula: density = mass / volume. This means that you need to measure the mass of the fluid and its volume in order to calculate its density.
The units used for density are typically grams per cubic centimeter (g/cm3) or kilograms per cubic meter (kg/m3). However, you can use any units as long as they are consistent for both mass and volume.
No, the ideal gas law is only applicable to gases at low pressures and high temperatures. Super critical fluids do not behave like ideal gases, so this equation cannot be used to calculate their density.
In general, as temperature and pressure increase, the density of a super critical fluid decreases. This is because at higher temperatures and pressures, the molecules of the fluid are more spread out and have more space between them, resulting in a lower density.
Yes, there are several methods for measuring the density of a super critical fluid, including pycnometry, vibrating tube densitometry, and pressure-density correlation methods. Each method has its own advantages and limitations, so it is important to choose the most appropriate method for your specific fluid and conditions.