How do I calculate the enthalpy change for this reaction?

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To calculate the enthalpy change for the combustion of methane, the heat produced is determined using the formula mass x specific heat capacity x change in temperature. In this case, the heat produced from burning 90 cm³ of methane raises the temperature of 100 cm³ of water from 20.0°C to 50.0°C, resulting in an enthalpy change of -12.54 kJ. However, it's important to clarify that enthalpy of combustion is defined as the change in enthalpy of the total reacting system. The discrepancy with the textbook answer may stem from a misunderstanding of this definition or the specific details of the calculation. Accurate results depend on correctly applying these principles.
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When 90cm^3 of methane is burned, the heat produced is used to raise the temperature of 100 cm^3 of water from 20.0°C to 50.0C. Calculate the enthalpy change for the reaction.

I'm not getting the same answer as the textbook...Please tell me whether my method is correct

All you do here is use the formula mass x specific heat capacity x change in temp. So,
the enthalpy change would be -(100/1000) x (4.18) x (30) = -12.54 KJ ?
 
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2. You've found the heat produced in burning 90cc of methane. How is the enthalpy of combustion defined?
 
the change in enthalpy of the total reacting system
 
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