How do I calculate the period of a wave using frequency and time increments?

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To calculate the period of a wave using frequency and time increments, first note that each increment represents 675 ms and there are 5 increments per wavelength. The total time for one wavelength is 5 increments multiplied by 675 ms, which equals 3375 ms or 3.375 seconds. The period can be directly obtained from this total time rather than calculating frequency first. The formula for period is simply the total time for one wavelength, confirming that the period is 3.375 seconds. Understanding the relationship between period and frequency simplifies the calculation process.
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:cry: Let' say you have a wave plotted out on a time scale. Each increment on the line is 675 ms. There are 5 increments between each wavelength. How would I find the frequency so that I can solve for the wave's period using:

Period = 1/Hz
 
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What's the problem? Just read the scale. The period is the number of seconds it takes for one wavelength to pass by right? There are 5 increments in one wavelength and 1 increment is 675 ms, so how many seconds for one wavelength?
 
The problem is I get 2.96E-4 when I multiply 675*5 then divide 1 by that. I must be doing it wrong
 
Why divide if you need the period? Also, check your units (dimensions). Period has the dimension of time, so it's measured in seconds.
 
StotleD : What Galileo is telling you is that you can directly read the period off the scale. You do not have to find the frequency and then invert it.
 
Period = 1/Hz
 
ok, thanks
 
StotleD said:
:cry: Let' say you have a wave plotted out on a time scale. Each increment on the line is 675 ms. There are 5 increments between each wavelength. How would I find the frequency so that I can solve for the wave's period using:

Period = 1/Hz
Code:
[FONT=Courier New]
                x               
              x   x
            x       x 
          x           x           x
                        x       x      
                          x   x
                            x
          |<--------------------->| 
           5x(675 ms) = The Period (directly from graph)

           Frequency = 1/(Period) = 1/(5x(675 ms))
           Period = 1/(Frequency) = 1/1/(5x(675 ms)) = (5x(675 ms)) AGAIN!
 

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