How do I evaluate this trigonometric integral involving cosine?

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Homework Statement


evaluate the integral.


Homework Equations


integral (pi/6 to pi/4) [(sin2x)^4 / sqrt(1-cos2x) dx]


The Attempt at a Solution


1. multiplying by conjugate: sqrt(1+cos2x)/sqrt(1+cos2x) .
2. should i split the (sin2x)^4 into (1-(cos2x)^2)^2 ?
 
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